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Easy: Quadratics
The tangent line touches the curve at (a, f(a)) with slope f′(a). Find the point by substituting a into f, find the slope by substituting a into f′, then use point-slope form y − f(a) = f′(a)(x − a) and rearrange to y = mx + b.
Write the equation of the tangent line at the given x-value, in slope-intercept form.
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A point and a slope. The point is (a, f(a)) and the slope is f′(a). Then use point-slope form: y − f(a) = f′(a)(x − a).
f(a) is the height of the curve; f′(a) is how steep it is there. Using f(a) as the slope is a common mix-up.
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